2) Summing the squares of equations 1 and 2: a^2 (sin^2 2Y + cos^2 2Y) = b^2 (sin^2 2X + cos^2 2X) a^2 = b^2 From question: a cos 2Y + b cos 2X = c sum equation 1 to obtain: 2a cos 2Y = c …

2 Answers Nghi N · Rhys Dec 17, 2017 Develop the left side by using the trig identity: #sin 2x -= 2sin x*cos x#

Use definition of tangent and Pythagorean's identity Answer: sin^2x Simplify 1-sin^2x/tan^2x Note that tanx=sinx/cosx We can substitute tan^2x=sin^2x/cos^2x =1-sin^2x/(sin^2x/cos^2x) =1 …

How do you find the values of the six trigonometric functions of an angle in standard position if a point with # (5, -3)# has on its terminal side?

Now we use the sine and cosine sum of multiple angle identities:

How do you prove that # (tan theta-cos theta)^2+ 4 sintheta= (tan theta+ cos theta)^2#?

May 21, 2017 · Given sin2 θ + cos2 θ = 1, sin θ = 8√185 185, and π 2 ≤ θ ≤ 3π 2, what is the value of tan θ?

Now according to your question, Sin x is positive and cos x is negative. This is only possible in the second quadrant of the cartesian plane, where Sin x is positive, and Cos x & Tan x are negative.

Jul 4, 2016 · If an integrand is a rational function of the trigonometric functions, the substitution #z=tan (x/2)#, or its equivalent #sin x= (2z)/ (1+z^2)# and #cos x= (1-z^2)/ (1+z^2)# and

"See below". x = a /(cos^3 theta) y = b sin^3theta/cos^3theta then x/y = a/b sin^3 theta and then theta =arcsin( root(3)((bx)/(ay)))